Solve the simultaneous equations: 6x - 5y = 17, 3x + 8y = 10

First, you will need to make one of the variables x or y have the same number in front. To do this just multiply the equation by a constant which will give you lets say the x value in this equation with the same constant in both equations. The lowest common multiple of 6 and 3 is 6. So the first equation remains the same and the second equation is multiplied by 2 to result in 6x + 16y = 20. Now the equations can be subtracted by each other to get rid of the x value and allow you to solve for y. This will result in (6x - 6x) + (16y--5y) = (20-17) . Leaving you with 21y = 3.To get the value for y just divide 3 by 21 which will give you the fraction 1/7 for y and plug this into any of the original equations to solve for x, which will give you 6x -5*(1/7) = 17. Rearrange to give 6x = 124/7. x = (124/7)/6 = 62/21.

JS
Answered by Jagjit S. Maths tutor

4110 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

What does Pythagoras's theorem state?


A cylinder has dimensions: diameter = 4x+2 and height = 4. Work out the volume of this cylinder. Give your answer in terms of x


There are n sweets in a bag. 6 of the sweets are orange. The rest of the sweets are yellow. Hannah takes a sweet from the bag and eats it. Hannah then takes at another sweet. The probability that Hannah eats two orange sweets is 1/3. Show that n²-n-90=0


Expand and simplify (x+5)(x+7)


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2025 by IXL Learning