Solve the simultaneous equations: 6x - 5y = 17, 3x + 8y = 10

First, you will need to make one of the variables x or y have the same number in front. To do this just multiply the equation by a constant which will give you lets say the x value in this equation with the same constant in both equations. The lowest common multiple of 6 and 3 is 6. So the first equation remains the same and the second equation is multiplied by 2 to result in 6x + 16y = 20. Now the equations can be subtracted by each other to get rid of the x value and allow you to solve for y. This will result in (6x - 6x) + (16y--5y) = (20-17) . Leaving you with 21y = 3.To get the value for y just divide 3 by 21 which will give you the fraction 1/7 for y and plug this into any of the original equations to solve for x, which will give you 6x -5*(1/7) = 17. Rearrange to give 6x = 124/7. x = (124/7)/6 = 62/21.

JS
Answered by Jagjit S. Maths tutor

3958 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

Calculate 64^2/3. (No calculator)


Please expand the brackets in the following equation to get a quadratic equation. Then, please show using the quadratic formula that the solutions to the equation are x=3 and x=5. Here is the starting equation: (x-3)(x-5)=0


Solve the equation x^2-9x+20=0


How do you use SOH CAH TOA?


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences