85 cm^3 of 0.05 mol/dm^3 sulfuric acid is used to neutralise 15 cm^3 of sodium hydroxide of an unknown concentration. Given that the chemical formula of the reaction is 2NaOH + H2SO4 => NA2SO4 + 2H2O, find the concentration of the sodium hydroxide.

Firstly, calculate the number of moles of sulfuric acid that reacts with the sodium hydroxide, using the equation; n = MV/1000 , where n is the number of moles, M is the concentration (in mol/dm3), and V is the volume (in cm3). n = (0.05 x 85)/1000 = 0.00425 mol. Looking at the equation for the neutralisation reaction; 2NaOH + H2SO4 => NA2SO4 + 2H2O , it can be seen that 1 mol of sulfuric acid reacts with 2 mol of sodium hydroxide. Therefore, the number of moles of sodium hydroxide in the solution is 2 x 0.00425 = 0.0085. Rearranging the previous equation to be able to find the concentration; M = 1000n/V , Therefore the concentration of sodium hydroxide can be found; (1000 x 0.0085)/15 = 0.566666 = 0.567 mol/dm3

JN
Answered by Joshua N. Chemistry tutor

3229 Views

See similar Chemistry GCSE tutors

Related Chemistry GCSE answers

All answers ▸

Why does graphite conduct electericity but diamond does not if both substances have a giant covalent structure?


How do I balance the chemical equation: C2H4 + O2 --> CO2 +H2O


Give the name of the monomer used to make poly(chloroethene). And describe how monomer molecules form polymer molecules.


What mass of sodium hydroxide would need to be dissolved to make 100 cm^3 of a 0.5 mol dm^-3 solution? (3 marks)


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences