Find the minimum value of the function, f(x)= x^2 + 5x + 2, where x belongs to the set of Real numbers

We first differentiate f(x), and we get f'(x)=2x + 5. We then set this equal to 0 and then solve for x. We get that xmin= -2.5. We check whether this was indeed a minimum, by calculating the second derivative, f''(xmin)= 2. Since f''(x) > 0 we know that xmin is indeed a (local) minimum. Then to find the minimum value of f(x), we substitute the value of x back to the equation and get the minimum value of f(x) is -4.25 ((-2.5)^2 + 5(-2.5) + 2 = -4.25))

PP
Answered by Pavlos P. Maths tutor

3296 Views

See similar Maths A Level tutors

Related Maths A Level answers

All answers ▸

How do you integrate (sinx)^3 dx?


Express 2 cos x – sin x in the form Rcos( x + a ), where R and a are constants, R > 0 and a is between 0 and 90 ° Give the exact value of R and give the value of to 2 decimal places.


Find the area bounded by the curve x^2-2x+3 between the limits x=0 and x=1 and the horizontal axis.


Given y = x(3x+ 5)^3. Find dy/dx.


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2025 by IXL Learning