ABCDEFGH is a cuboid. AB=5.6 cm CH=7.2cm. Angle BCA=44degrees. Find the size of the angle between AH and the plane ABCD giving your answer correct to one dp.
Remember: sinθ=opposite/hypotenuse cosθ=adjacent/hypotenusetanθ=opposite/adjacentAC=5.6/sin(44) = 8.0615...We can then use this length to calculate the angle between AH and the plane ABCD (here would be angle HAC) Tanθ= 7.2/8.0615 =0.8931θ=tan^-1 (0.8931) = 41.7690 degreesto one decimal place the angle formed =41.8 degrees
AR
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