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If a curve has equation y=(4/3)x^3-2x^2-24x+16, find dy/dx and find the coordinates of the turning points.

y=(4/3)x3-2x2-24x+16Step 1: Understand the questiondy/dx means differentiate the function of y with respect to xturning points are where the gradient of the function changes and will be found by setting dy/dx = 0 [note dy/dx = 0 is not always a turning point]Step 2: Solve the problemdy/dx = 4x2-4x-24simplifies to: dy/dx = x2-x-6now to find turning points: set dy/dx=0 such that x2-x-6=0 which factorises out as (x+2)(x-3)=0Thus, the roots to the equation are x=-2 and x=3Then to find coordinates, sub the x values back into equation to find their corresponding y valuesThus, final solution is (-2, 136/3) and (3,-38)Step 3: Reflect and consolidate learningUnderstand what you have solved - you have found local maxima and minima pointsPotential further qs: is a stationary point necessarily a turning point?, how can you show that these points are turning points?

Answered by Johann P. Maths tutor

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Answered by Johann P.
Maths tutor

66 Views

See similar Maths GCSE tutors
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