Sketch the curve y=x^2-x-6

This curve is a quadratic due to the highest power in the equation being two. Quadratics typically have the shape of a U. Due to the coefficient of the x^2 term being positive, the curve is increasing for larger values of x. To find where the curve crosses the x-axis we equate the equation to zero and factorise. This results in (x-3)(x+2)=0 so the curve crosses the x-axis at either 3 or -2. This is because for the equation to be true, either x-3=0 or x+2=0. The graph crosses the y-axis when x=0, therefore at -6. The minimum of the graph can be found by completing the square. Hence y=(x-1/2)^2-25/4 and so the minimum occurs at (1/2,-25/4).

MA
Answered by Masum A. Maths tutor

7077 Views

See similar Maths A Level tutors

Related Maths A Level answers

All answers ▸

a) Point A(6,7,2) lies on l1. Point B(9,16,5) also lies on l1. Find the distance between these two points. b) l2 lies in the same z plane as l1 and crosses l1 at A and is perpendicular to l1. Express l2 in vector form.


How do I maximise/minimise a given function f(x)?


1. (a) Find the sum of all the integers between 1 and 1000 which are divisible by 7. (b) Hence, or otherwise, evaluate the sum of (7r+2) from r=1 to r=142


How do you divide polynomials? How do you do it with remainder?


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2026 by IXL Learning