Solve the simultaneous equation: 2x + 3y = 6, 3x + 2y = 5.

1) 2x + 3y = 6

2) 3x + 2y = 5

We can either use substitution or elimination.

Using elimination:

Multiply equation 1) by 3 and multiply equation 2) by 2.

1) 6x + 9y = 18

2) 6x + 4y  = 10

Equation 1) - Equation 2)

5y = 8

y = 8/5

Substitue y back into either 1) or 2).

6x + (32/5) = 10

6x = 10 - (32/5)

x = 3/5

AN
Answered by Aaquib N. Maths tutor

16718 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

Solve the following simultaneous equations: A. 2x-2y=18 and B. 3x+y=23


Rearrange the following making a the subject: (a+2)/5 = 3a+b


How do I expand a factorised expression?


A)Write x^2 – 8x + 25 in the form (x – a)^ 2 + b. (B) Write down the coordinates of the turning point of the graph of y = x2 – 8x + 25. (C)Hence describe the single transformation which maps the graph of y = x2 onto the graph of y = x2 – 8x + 25.


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences