Given that f(x) = 1/x - sqrt(x) + 3. Find f'(1).

We are given that f(x) = 1/x - sqrt(x) + 3. Here, f(x) represents a function. A function is a relation or expression involving one or more variables. We are able to differentiate f(x) in order to find the gradient, f'(x), at a particular point on the graph. So the purpose of this question is to find the gradient of f(x) at x=1.
In order to differentiate quadratics, we use the typical formula where y=ax^b and dy/dx=abx^b-1. With this information we are now able to differentiate f(x). To make f(x) simpler we write, f(x) = x^-1 - x^1/2 + 3. Using the formula for differentiation above, we deduce that f'(x) = -x^-2 - (1/2)x^-1/2. To conclude, we simply substitute x=1 into our formula for f'(x) and we obtain f'(1)= -3/2.