A linear sequence starts a + 2b, a +6b, a + 10b. The 2nd has a value of 8 and the 5th term has a value of 44. What are the values of a and b?

a + 6b = 8 5th term: a + 18b = 44
term 1: a + 6b = 8term 2: a + 18b = 44
term 2 - term 1: 12b = 36b = 36/12 = 3
a + 6b = 8a + 6(3) = 8a = 8-18 = -10

LR

Related Maths GCSE answers

All answers ▸

How would you solve a quadratic equation by factorising?


How do I solve simultaneous equations?


Solve 8(x + 3) = 36


Solve the simultaneous equations 4x + 5y = 13 and 3x - 2y = 27.