A linear sequence starts a + 2b, a +6b, a + 10b. The 2nd has a value of 8 and the 5th term has a value of 44. What are the values of a and b?

a + 6b = 8 5th term: a + 18b = 44
term 1: a + 6b = 8term 2: a + 18b = 44
term 2 - term 1: 12b = 36b = 36/12 = 3
a + 6b = 8a + 6(3) = 8a = 8-18 = -10

LR
Answered by Leonie R. Maths tutor

3373 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

Prove that n(n+5) + 2(n+3) is always a product of two numbers with a difference of 5.


A right-angled triangle has one angle size 60 degrees, and hypotenuse of length 32cm. Calculate the length of the side opposite the 60 degree angle, to 3sf.


Solve, using the quadratic formula, the equation x^2 +2x=35


Factorising Quadratics: x ^2 ​​ − x = 12


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2025 by IXL Learning