Find the positive value of x such that log (x) 64 = 2

Find the positive value of x such that logx64 = 2
Using the logarithm rules, we know that we can rearrange the given equation into the form:
x2 = 64
Knowing this, we square root both sides to get 
x = 8, x= -8
As the value of x must be positive, the solution must be 
x = 8

SG

Related Maths A Level answers

All answers ▸

How do I use the product rule for differentiation?


Find the solution(s) of 3(x^2)-6x+2=0


Rewrite (2+(12)^(1/2))/(2+3^(1/2)) in the form a+b((c)^(1/2))


let y=6x^-0.5+2x+1, find dy/dx.