Use integration to find the area of the region between the curve y = 4x^2 + 3x, the line x=1.25 and the y, x-axes.
May be useful to sketch the curve - see where it crosses each axis (0,0 in this case).Set limits on the integral of 0 and 1.25 as lower and upper bounds respectively. Integrate each of the terms individually, applying the rule whereby the power increases by one and the term is divided by the new power's value. This yields[4/3x3 + 3/2x2] with limits of 0 and 1.25. Inserting these values gives 0 and ~4.95 respectively. A constant is not needed here as the integral is not indefinite (although this should be acknowledged and it should be understood why and where one is needed).Area is therefore 4.95 units squared.
