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### In triangle ABC, right angled at B, AB = 3 cm and AC = 6 cm. Determine angle BAC and angle ACB.

Using the trignometric principles,

sin (ACB) = AB/AC = 3/6 = 1/2

Thus, angle ACB = 30 degrees

and angle BAC = 90 - angle ACB = 60 degrees

1 year ago

Answered by Piyush, a GCSE Maths tutor with MyTutor

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