(6^2 + 8^2)^1/2 = (125a^3)^1/3 Work out the value of a?

(62 + 82)1/2 = (125a3 )1/3(36+62)1/2 = (125a3 )1/31001/2 = (125a3 )1/3+/- 10 = (125a3 )1/3Using +10 as the left-hand side answer:10 = (125a3 )1/31000 = 125a3 8 = a32 = aUsing -10 as the left-hand side answer:-10 = (125a3 )1/3-1000 = 125a3 -8 = a3-2 = aPutting the answer back into the original question to check: a=2 and a=-2(62 + 82)1/2 = (125 x 23)1/3( 36 + 64) 1/2= (125 x 8)1/31001/2 = 10001/3 = 10(62 + 82)1/2 = (125 x (-2))1/3( 36 + 64) 1/2 = (125 x (-8))1/31001/2 = (-1000)1/3 = -10

KS
Answered by Kate S. Maths tutor

4056 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

How does Pythagoras Theorem work?


How to use the quadratic formula, using the following equation: x^2 + 3x - 4


Given 6x+2y=4 and 5x+y=8, solve the simultaneous equations to find x and y.


How to find the coordinates of the turning points of a curve on a graph


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2026 by IXL Learning