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Differentiate this equation: xy^2 = sin(3x) + y/x

y² + 2xy dy/dx = 3cos(3x) + 1/y - x/y² dy/dx thereforedy/dx = (3cos(3x) + 1/y - y²) / (2xy + x/y²)

Answered by Alexander E. • Maths tutor

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C1 June 2014 Q)4 - https://pmt.physicsandmathstutor.com/download/Maths/A-level/C1/Papers-Edexcel/June%202014%20QP%20-%20C1%20Edexcel.pdf

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