What is the equation of the straight line passing through the points (2,3) and (3,5)?

There are three steps to solving these types of straight line problems. 1) Find the gradient (slope) of the line. 2) Find the point slope formula. 3) Solve for y.1) The gradient (m) of the line between any two points (x1, y1) and (x2, y2) is given by m = (y2-y1)/(x2-x1). It does not matter which order we label the points in. In this case, we have m = (5-3)/(3-1) = 2/1 = 2. The gradient of the line is 2.2) The point slope formula is given by y - y1 = m(x - x1). Using (2,3) as (x1, y1) and m = 2 from part 1), we have y - 3 = 2(x - 2)3) Expanding the brackets on the right-hand side gives y - 3 = 2x - 4. Adding 3 to both sides of the equation gives y = 2x - 1. Therefore, the equation of the straight line is given by y = 2x - 1.

OM
Answered by Omar M. Maths tutor

5289 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

Solve x^2 = 4(x – 3)^2


The perimeter of a right angled triangle is 105cm. The lengths of its sides are in the ratio of 2:6:7. Work out the area of the triangle.


Expand (2x + 3)(x - 1)


Expand and simplify 4x(x+3) - (2x-3)2


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2025 by IXL Learning