How do you go about rearranging equations where the required subject appears on both sides? Such as making x the subject of 7x + a = 3x + b.

To rearrange any equation, you must always do the same to both sides.
If you take a number from one side, you must also take it from the other. If you divide a side by one number you must divide the other by the same number (and this applies to the whole of both sides, not just part of the side).

7x + a = 3x + b, make x the subject:
Begin by collecting like terms on each side (so all the terms involving x on one side, and all the other terms on the other side).

  1. Take 3x from both sides:
    7x + a - 3x = 3x + b - 3x
    4x + a = b
  2. Take a from both sides:
    4x + a - a = b - a
    4x = b - a
  3. Divide both sides by 4 (as x must be alone):
    (4x)/4 = (b - a)/4
    x = (b - a)/4 This is our answer

RT
Answered by Rachael T. Maths tutor

21812 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

Solve the simultaneous equations. 5x + y = 21 and x-3y = 9


What is the gradient of the line passing through the point (1,2) and (5,5)? What is the equation of this line? What is the equation of the line perpendicular to this line that passes through the origin (0,0)?


Test


solve this simulatneous equations (with clear algebraic working) : 5x-2y = 33 , 5x + 8y = 18


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2026 by IXL Learning