Solve the simultaneous equations x – 2y = 1 and x^2 + y^2 = 29.
Start by modifying the first equation and making a third x=2y+1x2 = (2y+1)2 x2=4y2+4y+1therefore, if we sub this 3rd equation into the 2nd equation we get :4y2+4y+1+y2=29 5y2+4y-28=0 5y2-10y+4y-28=0 5y(y-2)+14(y-2)=0 (y-2)(5y+14)=0 y=2 and y=-14/5 Hence, subbing y into original equations gives x= 5 and x= -23/5
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