Solve the simultaneous equations x – 2y = 1 and x^2 + y^2 = 29.

Start by modifying the first equation and making a third x=2y+1x² = (2y+1)² x²=4y²+4y+1therefore, if we sub this 3rd equation into the 2nd equation we get :4y²+4y+1+y²=29 5y²+4y-28=0 5y²-10y+4y-28=0 5y(y-2)+14(y-2)=0 (y-2)(5y+14)=0 y=2 and y=-14/5 Hence, subbing y into original equations gives x= 5 and x= -23/5