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Differentiate y = (3x^3+2x+7)/x^(1/2)

y = (3x^3+2x+7)/x^(1/2) = 3x^(5/2)+2x^(1/2)+7x^(-1/2)dy/dx = 15/2x^(3/2)+x^(-1/2)-3.5x^(-3/2)

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Answered by Joshua W. • Maths tutor

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