How can I derive an equation to find the sum of an arithmetic sequence?

This isn't a requirement of many courses but understanding and proving mathematics has order is what makes mathematics unique and enjoyable to many.
Imagine the sum of a sequence with n terms, denoted Sn, which has an initial value, a, and a constant value, d, added on to each term.
For example, my sequence could be:
1, 6, 11, 16... which would make a = 1 and d = 5.
Then Sn = 1 + 6 + 11 + 16 +...
So to be more general,
Sn = + (a+d) + (a+2d) + ...+ (a+(n-2)d) + (a+(n-1)d)
Sn = (a+(n-1)d) + (a+(n-2)d) +...+ (a+2d) + a [reverse Sn]
Add both the sums together: add the first term to the other first term, then the second to the other second and so on.
2Sn = (2a+(n-1)d) + (2a+(n-1)d) +...+ (2a+(n-1)d) + (2a+(n-1)d)
There are n amounts of (2a+(n-1)d), as there are n terms, so this can be factored out.
2Sn = n(2a + (n-1)d)
=> Sn = 0.5n(2a + (n-1)d)    [divide by 2]

RH
Answered by Rhys H. Maths tutor

4632 Views

See similar Maths A Level tutors

Related Maths A Level answers

All answers ▸

Work out the equation of the normal to the curve y = x^3 + 2x^2 - 5 at the point where x = -2. [5 marks]


a) Solve the following equation by completing the square: x^(2)+ 6x + 1= 0. b) Solve the following equation by factorisation: x^(2) - 4x - 5 = 0 c) Solve the following quadratic inequality: x^(2) - 4x - 5 < 0 (hint use your answer to part b)


I don't fully understand the purpose of integration. Could you please explain it to me?


Find the values of k for which the equation (2k-3)x^2 - kx + (k-1) = 0


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2026 by IXL Learning