Derive the formula for differentiation from first principles

For a curve of f(x) against x, we can take the general point (x, f(x)) on the curve. By moving horizontally along the x-axis a distance of h, we also have the point (x+h, f(x+h)) on the curve. The gradient of the straight line between these two points is equal to the change in f(x) divided by the change in x, which (using our pair of coordinate points) is (f(x+h)-f(x))/x+h-x. This can be simplified to (f(x+h)-f(x))/h.Therefore, in the limit as h tends to 0 and the second point approaches the first along the curve, the gradient of the line tends to f'(x). This means that f'(x)=limh->0(f(x+h)-f(x))/h.

NG
Answered by Nicola G. Maths tutor

4592 Views

See similar Maths A Level tutors

Related Maths A Level answers

All answers ▸

Find the area between the curves C_1, C_2 and the lines x=0 and x=1, where C_1 is the curve y = x^2 and C_2 is the curve y = x^3.


The equation: x^3 - 12x + 6 has two turning points. Use calculus to find the positions and natures of these turning points.


How do I differentiate (cosx)/x^2


Integrate 10x(x^1/2 - 2)dx


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2026 by IXL Learning