What's the proof for the quadratic formula?

Mathematics is a unique subject within which many equations that you encounter have lots of functions and can be derived from the basics. The quadratic formula for instance is incredibly useful to quickly solve quadratics (with real roots) that cannot be factorised: It seems at first very tricky indeed at the first glance on how to start, however it only requires GCSE knowledge for the proof; completing the square. We start with ax2+bx+c=0, where y=0 and the next steps follow: 1. Factorise out the 'a' a(x2+bx/a) +c=0. 2. Half the inside number&square the bracket&subtract square from inside to make the function equal to the previous line a[(x+b/2a)2-(b/2a)2] +c=0. 3. Expand the brackets a(x+b/2a)2-b2/4a +c=0. 4. Keep the 'x' term to one side a(x+b/2a)2. =b2/4a - c. 5. Combine the fractions a(x+b/2a)2 =(b2-4ac) /4a. 6. Divide by 'a' (x+b/2a)2 =(b2-4ac) /4a2 7. Square root both sides x+b/2a = √(b2-4ac) / 2a. 8. Make 'x' on its own by subtracting b/2a from both sides. Voila! x = [-b± √(b2-4ac)] / 2a.

AO
Answered by Azeem O. Maths tutor

5963 Views

See similar Maths A Level tutors

Related Maths A Level answers

All answers ▸

a) Differentiate and b) integrate f(x)=xcos(2x) with respect to x


Find the centre coordinates, and radius of the circle with equation: x^2 + y^2 +6x -8y = 24


Curves C1 and C2 have equations y= ln(4x-7)+18 and y= a(x^2 +b)^1/2 respectively, where a and b are positive constants. The point P lies on both curves and has x-coordinate 2. It is given that the gradient of C1 at P is equal to the gradient of C2 at P.


An object of mass 3kg is held at rest on a rough plane. The plane is inclined at 30º to the horizontal and has a coefficient of friction of 0.2. The object is released, what acceleration does the object move with?


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2026 by IXL Learning