prove that lnx differentiated is 1/x
let y = lnx therefore e^y = x then differentiating both sides we get: dy/dx (e^y) = 1 dy/dx = 1/(e^y) and as e^y = x dy/dx = 1/x when y = lnx
let y = lnx therefore e^y = x then differentiating both sides we get: dy/dx (e^y) = 1 dy/dx = 1/(e^y) and as e^y = x dy/dx = 1/x when y = lnx
