Loading

Loading

Let n be any whole number. Any odd number can be written as 2n+1. Any odd number squared is therefore (2n+2)^{2}=2n*2n+2*2n+1=4n^{2}+4n+1=4(n^{2}+n)+1. n^{2}+n is a whole number, so 4(n^{2}+1) is a multiple of 4. Therefore, any odd number squared is 1 more than a multiple of 4.