Solve the simultaneous equation: 2x + y = 18, x - y = 6

First, we simply label the two equations as 'Equation 1' and 'Equation 2' respectively. So we have: Equation 1: 2x + y = 18and Equation 2: x - y = 6. In simultaneous equations, there are two variables: x and y. We want to express one variable in terms of the other (x in terms of y or vice versa). There are many ways to do this but it is a good idea to choose one that is easiest for you. We can express x in terms of y by rearranging Equation 2. We add y to both sides of the equation which gives us: Equation 3: x = y + 6. We can now sub this into Equation 1 in order to find out what the value of y is. We know x = y + 6 so we sub in this equation into 2x. Therefore, Equation 1 becomes 2(y+6) + y = 18. When we expand the brackets out, we get 2y + 12 + y = 18. If we collect like terms, we can rewrite this as 3y = 6. To find the value of y, we simply divide both sides by 3 to get y = 2. We have solved one half of our simultaneous equation. We have found what y is but we now need to find x. This is easy if we use our Equation 3: x = y + 6. We simply sub in our value of y into Equation 3 which will give us: x = 2 + 6. Therefore we have found that x = 8. Thus our final solution can just be written as: x = 8, y = 2. We can check and double check our answers by subbing in these values into Equation 1 and 2 to see if they are true. If not, we have made a mistake. However, if they do work then we know we have definitely got the correct answer!

HM
Answered by Harry M. Maths tutor

4487 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

The point P has coordinates (4, 5). The point Q has coordinates (a, b). A line perpendicular to PQ is given by the equation 5x+3y=11. Find an expression for b in terms of a.


Solve 11 – 4y = 6y – 3


Find the point(s) of intersection of the graphs y=x^2+4x-21 and x+y=-27 using an algebraic method.


Q) The equation of a curve is y=(x+4)^2+7. Find the co-ordinates of the turning point


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2026 by IXL Learning