How would I differentiate something in the form of (ax+b)^n

To tackle this type of question you would need to differentiate by substitution by implying the chain rule.If we substitute ax+b for a single character,lets say q , the expression becomes q^n which is easier to differentiate,we now differentiate this and differentiate the substituted ax+b.We now multiply this together to get the derivative. We multiply the terms toghether because the chain rule states ,dy/dx=(dy/dq)*(dq/dx)

Related Maths A Level answers

All answers ▸

Find the gradient of y=6x^3+2x^2 at (1,1)


Differentiate f(x) = x sin(x)


Using the substitution u = 2 + √(2x + 1), or other suitable substitutions, find the exact value of 4 0 1 ∫ 2 (2 1) +√ +x dx giving your answer in the form A + 2ln B, where A is an integer and B is a positive constant


Find the set of values for which: x^2 - 3x - 18 > 0