Solve the following equations x^2-2x+4=0, x^2+4x+1=0

x2-2x+4= (x-2)(x-2)=0  x=-2 (double root)  

x2+5x+1=0

x1,2= -5+_ (52-4(1)(1) )0.5/2 

x1=4.8     x2=-0.2 (to 1 d.p.)

KF
Answered by Kyriakos F. Maths tutor

3379 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

Simplify fully (3x^2 -8x- 3)/(2x^2-6x)


Find the roots of the formula x^2 + 4x + 3 by factorising.


How do I solve the equation x^2 + 6 = -5x


What is the sum of the first 100 numbers of the following sequence- 4,12,36, 108, .........


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2026 by IXL Learning