Differentiate y=(sin(x))^(2)
Using the chain rule of dy/dx=dy/du * du/dx we label sin(x) as u. Now we differentiate u with respect to x, getting cos(x). Then we differentiate u2 , getting 2u. Mutiplying these together gets us 2u*cos(x). Clearly we don't want u anymore, so replace u with sin(x) and obtain 2sin(x)cos(x) as the final answer!
BH
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