Differentiate y=(sin(x))^(2)
Using the chain rule of dy/dx=dy/du * du/dx we label sin(x) as u. Now we differentiate u with respect to x, getting cos(x). Then we differentiate u2 , getting 2u. Mutiplying these together gets us 2u*cos(x). Clearly we don't want u anymore, so replace u with sin(x) and obtain 2sin(x)cos(x) as the final answer!
BH
Related Maths A Level answers
All answers ▸Why do you get e^x when you differentiate e^x
How do you find the gradient of a parametric equation at a certain point?
Using implicit differentiation, write the expression "3y^2 = 4x^3 + x" in terms of "dy/dx"
How do I find the cartesian equation for a curve written in parametric form?