Solve 4log₂(2)+log₂(x)=3

First, we should look at the laws of logarithms.log_ax+log_ay=log_axylog_ax-log_ay=log_a(x/y)klog_ax=log_ax^kWe can see that laws 1 and 3 might be helpful, so we simplify our equation.log₂2⁴ +log₂x=3log₂2⁴x=3log₂16x=3Next, we just have to rearrange for x. The inverse of a logarithm is an exponential, so put each side of the equation as a power of 2 (as this is the base of the logarithm). This allows us to remove the logarithm and exponential from one side and we just have to divide by 16 after this.2^log16x=2³16x=8x=1/2