Differentiate y=x^2 from first principles

y=x2dy/dx= Limh-->0( ((x+h)2-x2) / (x+h-x) )dy/dx= Limh-->0( (x2 + 2hx + h2 - x2) / h )dy/dx= Limh-->0( (h2 + 2hx) / h )dy/dx= Limh-->0( h + 2x )dy/dx= Limh-->0( h ) + 2xdy/dx= 2x

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Answered by Dipayan C. Maths tutor

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