Differentiate y=x^2 from first principles

y=x2dy/dx= Limh-->0( ((x+h)2-x2) / (x+h-x) )dy/dx= Limh-->0( (x2 + 2hx + h2 - x2) / h )dy/dx= Limh-->0( (h2 + 2hx) / h )dy/dx= Limh-->0( h + 2x )dy/dx= Limh-->0( h ) + 2xdy/dx= 2x

DC
Answered by Dipayan C. Maths tutor

5111 Views

See similar Maths A Level tutors

Related Maths A Level answers

All answers ▸

Find the equation of the tangent to the curve y=3x^3+x^2+5 at the point (1,9)


Given that f(x)= (3+x^2)(x^1/2-7x). Find f'(x) (5marks)


Find the integral of 3x-x^(3/2)


Find the area R under the curve when f(x)=xcos(x) between the limits x=0 and x=2


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences