Curve C has equation 4x^2- y^3 - 4xy +2^y = 0 , point P (-2, 4) lies on C, find dy/dx at the point P
Use implicit differentiation 1) 8x - 3y^2dy/dx - 4y - 4xdy/dx +2^y*ln2 * dy/dx = 0 You then sub in the points P (-2,4) 2) 8(-2) - 3(4)^2 *dy/dx - 4(4) - 4(-2) *dy/dx + 2^(4) *ln2 * dy/dx = 0 Rearrange to get dy/dx on the LHS3) dy/dx = 32 / (-40 + 16ln2)
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