Find dy/dx, given that y=(3x+1)/(2x+1)

Since the equation for y is given in the format y=u/v, the use of the quotient rule is the easiest way to find the differential of this equation. The quotient rule states, (vu'-uv')/v^2 is equal to the differential of u/vIn this situation u=3x+1 and v=2x+1. The first step to take would be to differentiate the individual parts of the equation so, u'=3 and v'=2.These 4 values can then be put into the quotient rule in order to reach the result of the differential. dy/dx=(3(2x+1)-2(3x+1))/(2x+1)^2, which can be simplified down to dy/dx=1/(2x+1)^2

Answered by Maths tutor

5504 Views

See similar Maths A Level tutors

Related Maths A Level answers

All answers ▸

Water is flowing into a rightcircular cone at the rate r (volume of water per unit time). The cone has radius a, altitude b and the vertex or "tip" is pointing downwards. Find the rate at which the surface is rising when the depth of the water is y.


Is the trapezium rule an exact method of integration?


Differentiate 3x^2+1/x and find the x coordinate of the stationary point of the curve of y=3x^2+1/x


Find the stationary points of the curve y (x)= 1/3x^3 - 5/2x^2 + 4x and classify them.


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2026 by IXL Learning