QUOTIENT RULE: [u(x) / v(x)]' = [u'(x)v(x) - u(x)v'(x)] / v^{2}We have: u(x) = x^{4} - 1, hence u'(x) = 4x^{3}v(x) = x^{4} + 1, hence v'(x) = 4x^{3}So we have: [(4x^{3})(x^{4} + 1) - (4x^{3})(x^{4} - 1)] / (x^{4} + 1)^{2}Expanding gives us: [4x^{7} + 4x^{3} - 4x^{7} + 4x^{3}] / (x^{4} + 1)^{2}Giving us a final answer of: [8x^{3}] / (x^{4} + 1)^{2}, and hence the integer n = 8

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