How do you rearrange x = (2y+1)/(3y+4) to get y in terms of x?
We first multiply both sides of the equation by (3y+4) to get x(3y+4)=2y+1. We then expand the left hand side to get 3xy+4x=2y+1. By rearranging the equation we get 3xy-2y=1-4x. We then factorise the left hand side to get y(3x-2)=1-4x. Finally, we divide both sides by (3x-2) to get y=(1-4x)/(3x-2).
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