Write π₯Β²+6π₯+11 in the form (π₯+a)Β²+b.
This question wants you to "complete the square". To start this question we put a = (coefficient of x)/2 = 6/2 = 3.So far we have π₯Β²+6π₯+11 = (π₯+3)Β²+b. We now need to find b. We can expand and simplify the right hand side to get π₯Β²+6π₯+11 = π₯Β²+6π₯+9+b. We should now be able to see that b=2. So π₯Β²+6π₯+11 = (π₯+3)Β²+2.
BP
