How would you differentiate ln(x^2+3x+5)?

Here we need to use the chain rule because we have a function (natural log) of another function (x^2+3x+5). Let u=x^2+3x+5, and differentiate lnu with respect to u, this gives us 1/u. Then we differentiate x^2+3x+5 with respect to x, so we get 2x+3. Now the chain rule says: dy/dx=dy/dudu/dx, so we have dy/dx = (1/u)(2x+3)=(2x+3)/(x^2+3x+5)

OH
Answered by Oli H. Maths tutor

23686 Views

See similar Maths A Level tutors

Related Maths A Level answers

All answers ▸

Two particles, A and B, are moving directly towards each other on a straight line with speeds of 6 m/s and 8 m/s respectively. The mass of A is 3 kg, and the mass of B is 2 kg. They collide to form a single particle of speed "v" m/s. Find v.


Find the set of values of x for which 3x^2+8x-3<0.


Sketch the curve y=x^2-x-6


Show that (1 - cos(2x)) / (1 + cos(2x)) = sec^2(x) - 1


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2025 by IXL Learning