Differentiate x^2 from first principles

Differentiation is about finding gradients of functions. With straight lines we take the "rise of run" - the change in y over the change in x. With curves e.g. f(x) = x^2 we need to use the same idea, only we need to construct an infinitesimally small triangle to be able to do this.
Take an arbitrary x value x1 and another point (x1 + h) where h is a small positive number. we can construct a triangle between these two points and work out the gradient (delta y/delta x). this is (f(x1 + h) - f(x1))/((x1+h) - x1). given f(x) = x^2, this evaluates to (delta y)/(delta x) = 2x1 + h. To make the triangle infinitesimally small, we need to keep decreasing the size of h. We can take a limit to do this. As a shorthand for lim h -> 0 (delta y)/(delta x), we write dy/dx. Thus dy/dx = lim h -> 0 (2x1 + h) = 2x1. i.e. the gradient of the x^2 @ x1 is 2x1.

Answered by Maths tutor

4281 Views

See similar Maths A Level tutors

Related Maths A Level answers

All answers ▸

Differentiate y=x/sin(x)


find dy/dx of x^1/2 + 4/(x^1/2) + 4


Maths C1 2017 1. Find INT{2x^(5) + 1/4x^(3) -5}


At t seconds, the temp. of the water is θ°C. The rate of increase of the temp. of the water at any time t is modelled by the D.E. dθ/dt=λ(120-θ), θ<=100 where λ is a pos. const. Given θ=20 at t=0, solve this D.E. to show that θ=120-100e^(-λt)


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences