A curve is defined by the parametric equations x = 3^(-t) + 1, y = 2 x 2^(t). Show that dy\dx = -2 x 3^(2t).

Write 3^(t) as an expression involving x : We can rewrite x = 3^(-t) + 1 as x - 1 = 3^(-t) ; equivalently, 3^(t) = (x-1)^(-1). Substitute this expression into y, to write y in terms of x: y = 2 x 3^(t) = 2 x (x-1)^(-1). Differentiate y with respect to x, using the power rule:dy\dx = -2(x-1)^(-2). Substitute in the expression for 3^(t):dy\dx = -2(x-1)^(-2) = -2 x (3^(t))^(2) = -2 x 3^(2t)

MK
Answered by Maleeha K. Maths tutor

3320 Views

See similar Maths A Level tutors

Related Maths A Level answers

All answers ▸

The curve y = 2x^3 -ax^2 +8x+2 passes through the point B where x = 4. Given that B is a stationary point of the curve, find the value of the constant a.


A curve C is defined by the equation sin3y + 3y*e^(-2x) + 2x^2 = 5, find dy/dx


What is the gradient of the quadratic function y=3x²?


How to express (4x)/(x^2-9)-2/(x+3)as a single fraction in its simplest form.


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2025 by IXL Learning