A curve is defined by the parametric equations x = 3^(-t) + 1, y = 2 x 2^(t). Show that dy\dx = -2 x 3^(2t).

Write 3^(t) as an expression involving x : We can rewrite x = 3^(-t) + 1 as x - 1 = 3^(-t) ; equivalently, 3^(t) = (x-1)^(-1). Substitute this expression into y, to write y in terms of x: y = 2 x 3^(t) = 2 x (x-1)^(-1). Differentiate y with respect to x, using the power rule:dy\dx = -2(x-1)^(-2). Substitute in the expression for 3^(t):dy\dx = -2(x-1)^(-2) = -2 x (3^(t))^(2) = -2 x 3^(2t)

MK
Answered by Maleeha K. Maths tutor

3158 Views

See similar Maths A Level tutors

Related Maths A Level answers

All answers ▸

Find d/dx (ln(2x^3+x+8))


Given a fixed parabola and a family of parallel lines with given fixed gradient, find the one line that intersects the parabola in one single point


The curve C has equation: 2x^2y + 2x + 4y – cos (piy) = 17. Use implicit differentiation to find dy/dx in terms of x and y.


Given that 5cos^2(x) - cos(x) = sin^2(x), find the possible values of cos(x) using a suitable quadratic equation.


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences