Differentiate the equation y = x^2 + 3x + 1 with respect to x.

A simple way to differentiate an equation with respect to x is to reduce each x components power by one and multiply each x component by their original power.

Looking at the equation y = x^2 + 3x + 1, the component x^2 will be reduced from a power of 2 to a power of 1 and multiplied by its original power 2 to give 2x. The component 3x is reduced from a power of 1 to a power of zero and multiplied by its original power of 1 to give 3. As 1 is a constant and not an x component it dissapears in the differentiated eqution.

This therefore gives an answer of dy/dx = 2x + 3.

Answered by Jake B. Maths tutor

3413 Views

See similar Maths A Level tutors

Related Maths A Level answers

All answers ▸

How do I find dy/dx for the following equation: (x^2) + 2y = 4(y^3) + lnx?


How can I find the equation of a line l which passes through the points (5,7) and (3, -1)


find the gradient of y=x3 X0=5


Differentiate y= 8x^2 +4x +5


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2024

Terms & Conditions|Privacy Policy