Given that x = 4sin(2y + 6), Find dy/dx in terms of x

x = 4sin(2y + 6)dx/dy = 4(2)cos(2y + 6)dx/dy = 8cos(2y + 6) ==> dy/dx = 1/8cos(2y + 6)sin²(2y + 6) + cos²(2y + 6) = 1cos(2y + 6) = √(1 - sin²(2y + 6))cos(2y + 6) = √(1 - x²/16)Hence, our final answer is:dy/dx = 1/8(√(1 - x²/16))dy/dx = 1/[2(16 - x²)^1/2]