Find the first three terms in the expansion of (4-x)^(-1/2) in ascending powers of x.

(4-x)-1/2 = (4 (1 - x/4))-1/2 = 1/2 (1 - x/4)-1/2 = 1/2 ( 1 + x/8 + 3x2/128 + ...) = 1/2 + x/16 + 3x2/256 + ...Therefore the first three terms are 1/2 + x/16 + 3x2/256

Related Maths A Level answers

All answers ▸

How do you integrate by parts?


Given that: y = 5x^3 + 7x + 3. What is dy/dx? What is d^2y/dx^2?


find the definite integral between limits 1 and 2 of (4x^3+1)/(x^4+x) with respect to x


Find the gradient of the equation y=e^2x.ln(4x^2) when x=5.