Find the tangent to the curve y = x^3 - 2x at the point (2, 4). Give your answer in the form ax + by + c = 0, where a, b and c are integers.

y = x³- 2xdy/dx = 3x² -2plugging in x = 2, therefore gradient = 10using the formula to get the equation of a line y -y₁=m(x - x₁)substitute y₁=4 and x₁=2 to get the answer-10x + y + 16 = 0