Find the tangent to the curve y = x^3 - 2x at the point (2, 4). Give your answer in the form ax + by + c = 0, where a, b and c are integers.
y = x3- 2xdy/dx = 3x2 -2plugging in x = 2, therefore gradient = 10using the formula to get the equation of a line y -y1=m(x - x1)substitute y1=4 and x1=2 to get the answer-10x + y + 16 = 0
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