Find the gradient, length and midpoint of the line between (0,0) and (8,8).

let x1 = 0, y1 = 0 in (0,0) and let x2 = 8 and y2 = 8 in (8,8). To find the gradient, we would do (y2 - y1)/(x2-x1) = 1. To find the length, we would do the square root of the following: (y2-y1)^2 + (y2-y1)^2 which gives us the square root of 128 and this simplifies to 8sqrt(2). For the midpoint, we would do ((x1+x2)/2,(y1+y2)/2) which gives (4,4).The reason why I have opted to use x1, x2, y1 and y2 is to generalise it for any numbers we are given.

JA
Answered by Jason A. Maths tutor

5112 Views

See similar Maths A Level tutors

Related Maths A Level answers

All answers ▸

How does one find the equation of a line passing through 2 points of a graph?


Find the integral I of e^(2x)*cos*(x), with respect to x


How can I find the equation of a line l which passes through the points (5,7) and (3, -1)


Find the indefinite integral of f(x)=(1-x^2)/(1+x^2)


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences