Find the gradient, length and midpoint of the line between (0,0) and (8,8).

let x1 = 0, y1 = 0 in (0,0) and let x2 = 8 and y2 = 8 in (8,8). To find the gradient, we would do (y2 - y1)/(x2-x1) = 1. To find the length, we would do the square root of the following: (y2-y1)^2 + (y2-y1)^2 which gives us the square root of 128 and this simplifies to 8sqrt(2). For the midpoint, we would do ((x1+x2)/2,(y1+y2)/2) which gives (4,4).The reason why I have opted to use x1, x2, y1 and y2 is to generalise it for any numbers we are given.

JA
Answered by Jason A. Maths tutor

6086 Views

See similar Maths A Level tutors

Related Maths A Level answers

All answers ▸

The first term of an infinite geometric series is 48. The ratio of the series is 0.6. (a) Find the third term of the series. (b) Find the sum to infinity. (c) The nth term of the series is u_n. Find the value of the sum from n=4 to infinity of u_n.


Given that y=(4x^2)lnx, find f"(x) when x=e^2


Differentiate 4(x^3) + 3x + 2 with respect to x


Given that f(x)= (3+x^2)(x^1/2-7x). Find f'(x) (5marks)


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2026 by IXL Learning