Integrate y=(x^2)cos(x) with respect to x.

This problem must be solved using integration by parts, since y is equal to the product of two functions of x. Let u=x^2, therefore u'=2x (u'=du/dx). Let v'=cos(x), therefore v=sin(x) (v'=dv/dx).Using the integration by parts formula: Intgrl(y)dx= uv - Intgrl(vu')dx (which is given on the A Level maths formula sheet), Intgrl(y)dx=x^2(sin(x)) - Intgrl(2x(sin(x))dx). We must apply the same rule again, since 2x(sin(x)) cannot be integrated directly. u=2x, u'=2v'=sin(x), v=-cos(x). Intgrl(y)dx=x^2(sin(x)) - [-2x(cos(x)) - intgrl(2(-cos(x))dx], -2cos(x) can now be integrated giving the final solution: Intgrl(y)=x^2(sin(x)) + 2x(cos(x)) - 2(sin(x)) + c.

AH
Answered by Antony H. Maths tutor

3724 Views

See similar Maths A Level tutors

Related Maths A Level answers

All answers ▸

Turning points of the curve y = (9x^2 +1)/3x+2


How would you go about integrating a function which has an exponential and a cos/sin term?


At time t = 0, a particle is projected vertically upwards with speed u m s–1 from a point 10 m above the ground. At time T seconds, the particle hits the ground with speed 17.5 m s–1. Find the value of u and T and evaluate the model. (AS mechanics)


(i) Prove sin(θ)/cos(θ) + cos(θ)/sin(θ) = 2cosec(2θ) , (ii) draw draph of y = 2cosec(2θ) for 0<θ< 360°, (iii) solve to 1 d.p. : sin(θ)/cos(θ) + cos(θ)/sin(θ) = 3.


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2025 by IXL Learning