Given f(x) = 7(e^2x) * (sin(3x)), find f'(x)

f(x) = 7e2x sin(3x) Chain rule: f(x) = uv → f'(x) = u'v + uv' u = 7e2x u' = 14e2x v = sin(3x) v' = 3cos(3x) f'(x) = 14e2xsin(3x) + 7e2x 3cos(3x) f'(x) = 7e2x ( 2 sin (3x) + 3 cos (3x) )

CK
Answered by Chris K. Maths tutor

3816 Views

See similar Maths A Level tutors

Related Maths A Level answers

All answers ▸

How do you differentiate a polynomial?


Expand and simplify (3 + 4*root5)(3 - 2*root5)


Use the addition formulas: sin(x+y)=sin(x)*cos(y)+sin(y)*cos(x), cos(x+y)=cos(x)*cos(y)-sin(x)*sin(y) to derive sin(2x), cos(2x), sin(x)+sin(y).


Find two values of k, such that the line y = kx + 2 is tangent to the curve y = x^2 + 4x + 3


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2025 by IXL Learning