Given f(x) = 7(e^2x) * (sin(3x)), find f'(x)

f(x) = 7e2x sin(3x) Chain rule: f(x) = uv → f'(x) = u'v + uv' u = 7e2x u' = 14e2x v = sin(3x) v' = 3cos(3x) f'(x) = 14e2xsin(3x) + 7e2x 3cos(3x) f'(x) = 7e2x ( 2 sin (3x) + 3 cos (3x) )

CK
Answered by Chris K. Maths tutor

4080 Views

See similar Maths A Level tutors

Related Maths A Level answers

All answers ▸

Integrate cos^2(x)


Find the centre and radius of the circle with the equation x^2 + y^2 - 8x - 6y - 20 = 0.


A curve has parametric equations x = 1 - cos(t), y = sin(t)sin(2t) for 0 <= t <= pi. Find the coordinates where the curve meets the x-axis.


If given two parametric equations for a curve, how would you work out an equation for the gradient?


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2026 by IXL Learning