Solve these simultaneous equations: 2x + 3y = 19 and x + 4y = 17.
By multiplying everything in equation 2 by 2, you get 2x + 8y = 34. If you then subtract equation 1 from this you get 5y = 15. Thus y = 3, going back to equation two, and subbing y back in, x + 12 = 17, therefore x = 5.
JH
Related Maths GCSE answers
All answers ▸Bag A contains £7.20 in 20p coins. Bag B contains only 5p coins. The number of coins in bag B is three-quarters of the number of coins in bag A. How much money is in bag B?
write x^2 + 10x - 6 in the form (x+a)^2 + b
Find the equation of the line that passes through ( 5 , -4 ) and (3,8).
root3 (root6 + root12) can be written as Aroot2 + B