Solve the simultaneous equations: 6x - 5y = 17, 3x + 8y = 10

First, you will need to make one of the variables x or y have the same number in front. To do this just multiply the equation by a constant which will give you lets say the x value in this equation with the same constant in both equations. The lowest common multiple of 6 and 3 is 6. So the first equation remains the same and the second equation is multiplied by 2 to result in 6x + 16y = 20. Now the equations can be subtracted by each other to get rid of the x value and allow you to solve for y. This will result in (6x - 6x) + (16y--5y) = (20-17) . Leaving you with 21y = 3.To get the value for y just divide 3 by 21 which will give you the fraction 1/7 for y and plug this into any of the original equations to solve for x, which will give you 6x -5*(1/7) = 17. Rearrange to give 6x = 124/7. x = (124/7)/6 = 62/21.

JS
Answered by Jagjit S. Maths tutor

4609 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

Integrate x^2 + 1/ x^3 +3x +2 using limits of 1 and 0


A tank contains 45 000 cm3 of water. The tank leaks at 0.75 litres/minute. How long does the tank take to empty?


Please explain the difference between compound and simple interest


What is the highest common factor of 24 and 90?


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2026 by IXL Learning