Solve the simultaneous equations: 6x - 5y = 17, 3x + 8y = 10

First, you will need to make one of the variables x or y have the same number in front. To do this just multiply the equation by a constant which will give you lets say the x value in this equation with the same constant in both equations. The lowest common multiple of 6 and 3 is 6. So the first equation remains the same and the second equation is multiplied by 2 to result in 6x + 16y = 20. Now the equations can be subtracted by each other to get rid of the x value and allow you to solve for y. This will result in (6x - 6x) + (16y--5y) = (20-17) . Leaving you with 21y = 3.To get the value for y just divide 3 by 21 which will give you the fraction 1/7 for y and plug this into any of the original equations to solve for x, which will give you 6x -5*(1/7) = 17. Rearrange to give 6x = 124/7. x = (124/7)/6 = 62/21.

JS
Answered by Jagjit S. Maths tutor

4725 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

There are 30 yellow sweets and 10 black sweets in a bag. Two sweets are taken out at random without replacement. Work out the probability that the two sweets are the same colour.


There are only red , blue and purple counters in a bag. The ratio of the number of red counters to the number of blue counters is 3 : 17. If a counter is taken randomly the probability that it is purple is 0.2 Work out the probability for it to be red.


Work out area of shaded region in terms of pi. (https://prnt.sc/hqfbsl) [Question link]


What is differentiation and what does it actually mean?


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2026 by IXL Learning