How do i solve the quadratic x^2 + 5x + 6 = 0 ?

So we can always substitute the right terms into the quadratic formula. However, there might be a quicker way. Lets try and see if the quicker ways work.Firstly, we need to spot weather the difference of two squares applies to this equation. However, as there are three terms in the equation, this cannot be the case. Difference of two squares is when the solution to x^2 - 25 is (x + 5)(x - 5). Then we can try and find two numbers that multiply to produce 6 and add together to produce 5. Lets try and factorise 6 first. The pairs that we obtain are:1,62,3Thats all. These pairs are all factors of 6. Lets try and spot if any of them add up to produce 5!The pair 2 and 3 do! So they multiply to produce 6 and add together to produce 5. We have sucessfully found our roots to the quadratic equation. So the last step is to rewrite it in the form (x + 2)(x + 3) = 0 if needed.if our roots were -2 and -3, we would have (x + (-2))(x + (-3)) = 0. Which would be rewritten as (x - 2)(x - 3) = 0.Please note that sometimes the numbers aren't nice enough to use this method. In which case, the quadratic formula would be our best bet. 

TS
Answered by Tarun S. Maths tutor

9977 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

A cuboid has sides such that the longest side is two units more than the shortest side, and the middle length side is one unit longer than the shortest side. The total surface area of the cuboid is 52 units². Calculate the length of the shortest side.


how do you factorise a quadratic where there is a number in front of the x squared?


Simplify the following: ((1/3)(c^2))^3


A right-angled triangle has an adjacent of (x + 1) and (x - 1). (a) Find the length of the hypotenuse in terms of x. (b) Explain why the triangle can't be an isoceles triangle.


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences