Find the coordinates of the turning point of the equation y =x^2-8x+10

We know that the turning point of this quadratic will be a minimum point because the coefficient of x2 is positive (1). To find the turning point, we must complete the square: y= (x-4)2 -16 +10 so y= (x-4)2-6. Since the value of the brackets is a square number, it must be greater than or equal to 0, so the smallest number y can be is equal to when the brackets is 0. y = (0)2-6. So at the minimum point, y =-6. Since the brackets must equal 0, x-4 = 0 so x=4. Hence the turning point is at (4,-6)

SR
Answered by Sita R. Maths tutor

5588 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

Expand and simplify fully 4(x - 2) - 2(3 - 5x)


Write sqrt(75) in simplified surd form.


Bill buys 8 identical cricket balls. The total cost is £169.04 Work out the total cost of 19 of these cricket balls. (Calculator allowed).


when given that y is 20% bigger than x, how can you express this as a ratio of y to x?


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences