Show that (x+1)(x+2)(x+3) can be written as ax^3+bx^2+cx+d

Start by multiplying any 2 brackets together: (x + 1)(x + 2): Split the 1st bracket: x(x+2) + 1(x+2) = x^2 + 2x + x + 2 = x^2 + 3x + 2 Then multiply that answer with the last bracket: (x + 3)(x^2 + 3x + 2): Split the 1st bracket: x(x^2 +3x + 2) +3(x^2 +3x + 2)= x^3 + 3x^2 + 2x + 3x^2+ 9x + 6 = x^3 + 6x^2 + 11x + 6 . a = 1, b = 6, c = 11, d = 6.