Solve (2x+3)(4x-2)=0

To solve a simulatious equation, you should place the contents of each bracket equal to 0.
so (2x+3)=0 and (4x-2)=0
Lets start with the equation on the left.
2x+3=0
Minus 3 from both sides of the equation leaving you with 2x=-3 Then divide both sides by 2 leaving the equation at x= -3/2 - this is your answer

for the equation on the right (4x-2)=0
4x-2=0
add 2 to both sides (as adding is opposite to minusing) giving you 4x=2 divide both sides by 4 leaving you with the answer x=2/4
(Note: This answer can be further simplified by dividing both the top and the bottom of the fraction by the same number - in this case both the top and the bottom can be divided by 2, leaving the alternate answer as 1/2)

CP
Answered by Catherine P. Maths tutor

4807 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

Find the equation of the tangent to the curve y = x√x at the point (4,6).


A square is placed in a circle of area (49π)cm^2 such that all four vertices of the square lie on the circumference of the circle. What is the area of the square?


How do you solve quadratic inequalities?


How do you solve two simultaneous equations? (i.e. 5x + y =21 and x - 3y =9)


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2026 by IXL Learning